By AMIRA ZARGA

24 Sep 2013 08:11 English 10 Replies

hello

could any one tell me how to check if the GPS is actif in my mobile or emulator.

and in case if it is desabled can i load user to parameters application to activate his GPS or can i activate GPS from my application?

thx a lot and best regards

Amira

Edited on 18 03, 2014

Responses

10 Replies

talari praveen kumar

24 Sep 2013 09:11

Hi Amira There are no APIs to enable or disable GPS from application. By default GPS is disable in device (there is no GPS in emulator), you can enable it manually through settings->Location->GPS. You can only check whether your device supports GPS or not using tizen.systeminfo.getCapabilities() method.

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Maksym

26 Sep 2013 04:04

Is it possible to open settings->Location->GPS dirrectly from JS application?

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Marco Buettner

26 Sep 2013 06:06

Imo no

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AMIRA ZARGA

26 Sep 2013 06:31

i think yes, using application API. i'm going to do this later, i'll tell you how ones done :) but if you did it befor me do not hesitate to share

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AMIRA ZARGA

24 Sep 2013 10:47

thx a lot could you please tell me if it is possible to access setting from my application? i want to chow a message telling that gps is not actif and open setting that uwhere user cabn activate his gps?

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Lakshmi Grandhi

26 Sep 2013 07:04

Hi, To know whether GPS is enabled or not, Web Applications doesn't have functionality, but you can using hybrid application to know whether it is on or not using native apps. To launch setting app use Application control APis

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talari praveen kumar

26 Sep 2013 07:16

Hi Use the below code to launch 'settings' app

function onsuccess() {
        console.log("The application has launched successfully");
    }
function errorCallback(){console.log("failed");}
tizen.application.launch("kto5jikgul.Settings", onsuccess,errorCallback);

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Alexander AVSukhov

27 Sep 2013 05:27

Hello, For launch Setting -> Location you can use AppControl: var appControl = new tizen.ApplicationControl("http://tizen.org/appcontrol/operation/configure/location", null, null, null); tizen.application.launchAppControl( appControl, "tizen.settings", function() {console.log("launch application control succeed"); }, function(e) {console.log("launch application control failed. reason: " + e.message); }, null );

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Marco Buettner

27 Sep 2013 07:02

nice :) thanks

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AMIRA ZARGA

27 Sep 2013 07:10

thx Alexander AVSukhov i'll try this :)

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